What is the domain of f(x)=(sqrt(25-x^2)) ?

The domain of f(x)=(sqrt(25-x^2)) is -5<= x<= 5

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domain of f(x)=(sqrt(25-x^2))

domain

f (x) = (25 - x^{2})

- 5 \leq x \leq 5

Interval Notation

[- 5, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

The function domain

- 5 \leq x \leq 5

x + \frac{6}{x}

f (x) = - 6 x^{2} + 8 x - 10

- \frac{1}{- 5 x + 4}

f (x) = 16000 + 5 t - 20 t

\frac{1}{t + 2}

What is the domain of f(x)=(sqrt(25-x^2)) ?
The domain of f(x)=(sqrt(25-x^2)) is -5<= x<= 5