What is the domain of f(x)=log_{10}(1/5)(x^2-x-12) ?

The domain of f(x)=log_{10}(1/5)(x^2-x-12) is -infinity <x<infinity

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domain of f(x)=log_{10}(1/5)(x^2-x-12)

domain

f (x) = lo g_{10} (\frac{1}{5}) (x^{2} - x - 12)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

g (z) = 3 x^{2} - x + 5

f (x) = \frac{( 6 t - 1 )}{t ^{2} + 1}

f (x) = 1 + 2 sec (x)

f (x) = \frac{x + 8}{x + 3}

y = x^{2} (x^{2} - 5)

What is the domain of f(x)=log_{10}(1/5)(x^2-x-12) ?
The domain of f(x)=log_{10}(1/5)(x^2-x-12) is -infinity <x<infinity