What is the domain of f(x)=(x-1)/(3x+1) ?

The domain of f(x)=(x-1)/(3x+1) is x -1/3

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domain of f(x)=(x-1)/(3x+1)

domain

f (x) = \frac{x - 1}{3 x + 1}

x < - \frac{1}{3} or x > - \frac{1}{3}

Interval Notation

(- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{3}

The function domain

x < - \frac{1}{3} or x > - \frac{1}{3}

f (x) = 52 x - 6

y = \frac{2 x - 3}{2 x + 3} - 1

\frac{100}{x ^{2}} - 9

r (x) = \frac{x ^{2} + 5 x}{25 - x ^{2}}

- e^{x} - 6

What is the domain of f(x)=(x-1)/(3x+1) ?
The domain of f(x)=(x-1)/(3x+1) is x<-1/3 \lor x>-1/3