What is the domain of ln((x^2+3)/(3+5)) ?

The domain of ln((x^2+3)/(3+5)) is -infinity <x<infinity

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domain of ln((x^2+3)/(3+5))

domain

ln (\frac{x ^{2} + 3}{3 + 5})

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x + 8}{x + 7}

f (x) = \frac{- 1}{1 + x}

f (x) = x - 4 x^{2} - 9 g (x) = 1 x + 3

f (x) = \frac{1}{x ^{2} 2 x - 8}

f (x) = \frac{4}{x ^{2} + 100}

What is the domain of ln((x^2+3)/(3+5)) ?
The domain of ln((x^2+3)/(3+5)) is -infinity <x<infinity