What is the domain of g(x)=sqrt(2/(x-1)) ?

The domain of g(x)=sqrt(2/(x-1)) is x>1

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domain of g(x)=sqrt(2/(x-1))

domain

g (x) = \frac{2}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

y = \frac{1}{2} - ln (x^{2} - 4)

g (x) = \frac{∣ x - 4 ∣}{x - 4}

f (x) = \frac{( - 5 + x ) ( 5 + x )}{( 8 + x )}

e^{4 x}

y = lo g_{10} (x - 2) - \frac{1}{x + 2}

What is the domain of g(x)=sqrt(2/(x-1)) ?
The domain of g(x)=sqrt(2/(x-1)) is x>1