What is the domain of (sqrt(3x+54))/(3^x-81)+19-x^4 ?

The domain of (sqrt(3x+54))/(3^x-81)+19-x^4 is -18 4

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domain of (sqrt(3x+54))/(3^x-81)+19-x^4

domain

\frac{3 x + 54}{3 ^{x} - 81} + 19 - x^{4}

- 18 \leq x < 4 or x > 4

Interval Notation

[- 18, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 18

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 18 \leq x < 4 or x > 4

y = \frac{x ^{2}}{4 - x}

f (t) = t + 3

f (x) = \frac{23 x + 24}{x}

f (x) = - 3 + lo g_{2} (x - 2)

f (x) = - \frac{1}{( x - 2 ) ^{2}}

What is the domain of (sqrt(3x+54))/(3^x-81)+19-x^4 ?
The domain of (sqrt(3x+54))/(3^x-81)+19-x^4 is -18<= x<4\lor x>4