What is the domain of f(t)=sqrt(t+2) ?

The domain of f(t)=sqrt(t+2) is t>=-2

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domain of f(t)=sqrt(t+2)

domain

f (t) = t + 2

t \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 2

The function domain

t \geq - 2

f (x) = \frac{6 x}{5 x - 2}

f (x) = \frac{( 12 - x - x ^{2} )}{x + 2}

f (x) = - 3 x^{2} + 6 x + 1

f (x) = 2 x y - 3 y = 2 - 3 x

f (x) = \frac{6 x}{5 x - 1}