What is the domain of y=sqrt(1/(x-1)) ?

The domain of y=sqrt(1/(x-1)) is x>1

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domain of y=sqrt(1/(x-1))

domain

y = \frac{1}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = \frac{5 x}{x + 1}

\frac{( x + 10 - 4 )}{x - 6}

f (x) = lo g_{4} (x) + 5

x + 2 + \frac{1}{x ^{2} - x - \frac{3}{4}}

f (x) = \frac{( x 5 ^{x} )}{5 ^{(x + 2)} - 2}