What is the domain of y=x+sin(x),0<= x<= 2pi ?

The domain of y=x+sin(x),0<= x<= 2pi is 0<= x<= 2pi

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domain of y=x+sin(x),0<= x<= 2pi

domain

y = x + sin (x), 0 \leq x \leq 2 π

0 \leq x \leq 2 π

Interval Notation

[0, 2 π]

Solution steps

Set the domain to the given interval

0 \leq x \leq 2 π

The function has no undefined points nor domain constraints. Therefore, the domain is

0 \leq x \leq 2 π

4 x + 11

x 18 - x

f (x) = \frac{13}{x + 13}

x^{3} + 2 x^{2} - 5 x - 4

x^{3} + 2 x^{2} - 5 x - 6

What is the domain of y=x+sin(x),0<= x<= 2pi ?
The domain of y=x+sin(x),0<= x<= 2pi is 0<= x<= 2pi