What is the domain of h(x)=sqrt(289-x^2) ?

The domain of h(x)=sqrt(289-x^2) is -17<= x<= 17

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domain of h(x)=sqrt(289-x^2)

domain

h (x) = 289 - x^{2}

- 17 \leq x \leq 17

Interval Notation

[- 17, 17]

Solution steps

Find non-negative values for radicals:

- 17 \leq x \leq 17

The function domain

- 17 \leq x \leq 17

\frac{x}{7} + \frac{5}{7} + \frac{3 x + 15}{7 ( 7 x ^{2} - 3 )}

3 + x - 4

\frac{n}{x}

8 x^{4} - 40 x^{2}

ln (x + 2) + ln (x - 1)

What is the domain of h(x)=sqrt(289-x^2) ?
The domain of h(x)=sqrt(289-x^2) is -17<= x<= 17