What is the domain of f(x)=(1/(t^2)) ?

The domain of f(x)=(1/(t^2)) is t 0

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domain of f(x)=(1/(t^2))

domain

f (x) = (\frac{1}{t ^{2}})

t < 0 or t > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

t = 0

The function domain

t < 0 or t > 0

2 - 2 - x

f (x) = \frac{4 x + 1}{2 x}

f (x) = 19 x^{2} + 5

\frac{1}{( \frac{1}{x} ) - 1}

f (x) = \frac{x ^{3} - x - 1}{x ^{2} + x + 1}

What is the domain of f(x)=(1/(t^2)) ?
The domain of f(x)=(1/(t^2)) is t<0\lor t>0