What is the domain of f(x)= 1/(x^2+2x-3)+sqrt(x+2) ?

The domain of f(x)= 1/(x^2+2x-3)+sqrt(x+2) is -2 1

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domain of f(x)= 1/(x^2+2x-3)+sqrt(x+2)

domain

f (x) = \frac{1}{x ^{2} + 2 x - 3} + x + 2

- 2 \leq x < 1 or x > 1

Interval Notation

[- 2, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 1, x = - 3

Combine real regions and undefined points for final function domain

- 2 \leq x < 1 or x > 1

f (x) = - \frac{9}{50} x + 72

ln ∣ 2 x + 1 ∣ - sin (3 x - 2)

e^{x - 1} + 1

3 v^{2} - 75

f (x) = 0.5 (x - 6)^{2} - 3

What is the domain of f(x)= 1/(x^2+2x-3)+sqrt(x+2) ?
The domain of f(x)= 1/(x^2+2x-3)+sqrt(x+2) is -2<= x<1\lor x>1