What is the domain of f(x)=(sqrt(x+2))^2-5 ?

The domain of f(x)=(sqrt(x+2))^2-5 is x>=-2

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domain of f(x)=(sqrt(x+2))^2-5

domain

f (x) = (x + 2)^{2} - 5

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

200 - 4 x

f (x) = \frac{( x 5 ^{x} )}{5 ^{(x + 2)} - 6}

\frac{x}{ln ( x - 1 ) - 1}

f (x) = \frac{x + 1}{x ^{2} - 9 x + 8}

f (x) = - 3 x^{2} + x

What is the domain of f(x)=(sqrt(x+2))^2-5 ?
The domain of f(x)=(sqrt(x+2))^2-5 is x>=-2