What is the domain of g(x)=(x+9)/(x^2-1) ?

The domain of g(x)=(x+9)/(x^2-1) is x 1

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domain of g(x)=(x+9)/(x^2-1)

domain

g (x) = \frac{x + 9}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{4}{( x + 2 ) ^{2}} + 1

\frac{x + 2}{x - 1}

y, y \leq 3 x + 6

f (x) = [1.8]

f (x) = \frac{2 x - 4}{3 x - 3}

What is the domain of g(x)=(x+9)/(x^2-1) ?
The domain of g(x)=(x+9)/(x^2-1) is x<-1\lor-1<x<1\lor x>1