What is the domain of f(x)=(1/(x+1^2)) ?

The domain of f(x)=(1/(x+1^2)) is x -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(1/(x+1^2))

domain

f (x) = (\frac{1}{x + 1 ^{2}})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = lo g_{2} (x^{2} - x + 2)

f (x) = x^{2} + 3 x - 10

f (x) = x - 2 - 5 x - 1

\frac{1}{\frac{2 x}{4 x + 7}}

f (x) = x^{5} + x

What is the domain of f(x)=(1/(x+1^2)) ?
The domain of f(x)=(1/(x+1^2)) is x<-1\lor x>-1