What is the domain of f(x)=(4x(x-6))/(2x^2-5x-3) ?

The domain of f(x)=(4x(x-6))/(2x^2-5x-3) is x 3

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domain of f(x)=(4x(x-6))/(2x^2-5x-3)

domain

f (x) = \frac{4 x ( x - 6 )}{2 x ^{2} - 5 x - 3}

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

f (x) = \frac{x - 6}{x ^{2} - 1}

f (x) = \frac{e ^{8} - 1}{2}

\frac{1}{3} x

(x + 7) 2

lo g_{10} (\frac{x + 6}{x ^{2} - 4})

What is the domain of f(x)=(4x(x-6))/(2x^2-5x-3) ?
The domain of f(x)=(4x(x-6))/(2x^2-5x-3) is x<-1/2 \lor-1/2 <x<3\lor x>3