What is the domain of f(x)=sqrt(4-(x^2)) ?

The domain of f(x)=sqrt(4-(x^2)) is -2<= x<= 2

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domain of f(x)=sqrt(4-(x^2))

domain

f (x) = 4 - (x^{2})

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

\frac{- x ^{2} + 6}{x ^{2} + 4 x - 32}

y = 3 x^{2} - 6

f (x) = 3 x + 2, x \geq 0

y = 9 x - 44 x + 2

y = 5 - 2 x

What is the domain of f(x)=sqrt(4-(x^2)) ?
The domain of f(x)=sqrt(4-(x^2)) is -2<= x<= 2