What is the domain of f(x)=(-10)/(sqrt(z-3)) ?

The domain of f(x)=(-10)/(sqrt(z-3)) is z>3

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domain of f(x)=(-10)/(sqrt(z-3))

domain

f (x) = \frac{- 10}{z - 3}

z > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

z \geq 3

Find undefined (singularity) points:

z = 3

Combine real regions and undefined points for final function domain

z > 3

3 e^{1 - x^{2}} x^{2}

y = lo g_{2} (\frac{( x + 1 )}{x ^{2} - 9})

- 3 sin (3 x)

2 \cdot lo g_{2 x + 3} (x)

What is the domain of f(x)=(-10)/(sqrt(z-3)) ?
The domain of f(x)=(-10)/(sqrt(z-3)) is z>3