What is the domain of f(x)=log_{e}(|x+1|) ?

The domain of f(x)=log_{e}(|x+1|) is x -1

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domain of f(x)=log_{e}(|x+1|)

domain

f (x) = lo g_{e} (∣ x + 1 ∣)

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > - 1

The function domain

x < - 1 or x > - 1

\frac{- 3 x + 7}{x - 1}

f (x) = 5 - x (5 x^{2} + 4)

f (x) = ∣ 3 x - 9 ∣

1 - x^{2} + 5

f (x) = \frac{x - 7}{x ^{2} - 14 x + 49}

What is the domain of f(x)=log_{e}(|x+1|) ?
The domain of f(x)=log_{e}(|x+1|) is x<-1\lor x>-1