What is the domain of f(x)=sqrt(x)+x-18 ?

The domain of f(x)=sqrt(x)+x-18 is x>= 0

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domain of f(x)=sqrt(x)+x-18

domain

f (x) = x + x - 18

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

\frac{x - 1}{25 - x ^{2}}

f (x) = \frac{x ^{2} - 3 x - 28}{x + 4}

f (x) = \frac{3}{x - 2} + 2

f (x) = \frac{3}{x - 2} + 4

g (x) = x^{2} - 6 x

What is the domain of f(x)=sqrt(x)+x-18 ?
The domain of f(x)=sqrt(x)+x-18 is x>= 0