What is the domain of (x-6)-(sqrt(x+2)) ?

The domain of (x-6)-(sqrt(x+2)) is x>=-2

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domain of (x-6)-(sqrt(x+2))

domain

(x - 6) - (x + 2)

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

- x + 4 - x + 4

x^{2} - x + 6

\frac{3 x ^{2} + 1}{4}

f (x) = f (x) = 3 x + 7

\frac{x ^{2}}{x ^{4} + 3}

What is the domain of (x-6)-(sqrt(x+2)) ?
The domain of (x-6)-(sqrt(x+2)) is x>=-2