What is the domain of f(x)=(3x-5)/(x^2+8x+7) ?

The domain of f(x)=(3x-5)/(x^2+8x+7) is x -1

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domain of f(x)=(3x-5)/(x^2+8x+7)

domain

f (x) = \frac{3 x - 5}{x ^{2} + 8 x + 7}

x < - 7 or - 7 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 7) \cup (- 7, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 7

The function domain

x < - 7 or - 7 < x < - 1 or x > - 1

f (y) = ln \frac{x + 1}{x - 1}

f (x) = x^{2} + 10 x + 16

f (x) = x^{3} + 4 x^{2} - 2 x - 6

\frac{76}{x - 4}

\frac{( x - 3 )}{( 2 x - 7 )}

What is the domain of f(x)=(3x-5)/(x^2+8x+7) ?
The domain of f(x)=(3x-5)/(x^2+8x+7) is x<-7\lor-7<x<-1\lor x>-1