What is the domain of f(x)=sqrt(x+1),3 5 ?

The domain of f(x)=sqrt(x+1),3 5 is x>5

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domain of f(x)=sqrt(x+1),3<= x>5

domain

f (x) = x + 1, 3 \leq x > 5

x > 5

Interval Notation

(5, \infty)

Solution steps

Set the domain to the given interval

x > 5

Find non-negative values for radicals:

x \geq - 1

Join real regions with the domain:

x \geq - 1 and x > 5

x > 5

f (x) = x + x - 2

f (x) = \frac{1 - 2 x}{2 x}

f (x) = 0.15 (x - 1500) + 150

\frac{- x ^{2} + 4 x - 12}{32}

f (x) = \frac{x ^{2}}{x ^{2} + x - 12}

What is the domain of f(x)=sqrt(x+1),3<= x>5 ?
The domain of f(x)=sqrt(x+1),3<= x>5 is x>5