What is the domain of y=sqrt(2x+1)+4 ?

The domain of y=sqrt(2x+1)+4 is x>=-1/2

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domain of y=sqrt(2x+1)+4

domain

y = 2 x + 1 + 4

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

f (x) = (x^{2} - 144) x + 9

f (x) = \frac{8}{8 + 5 x}

y = \frac{36 - x ^{2} + 3}{x - 5}

3 x^{3} - 6 x^{2}

f (x) = - 2 (x^{2} + 1)