What is the domain of f(x)=(-13)/((x+4)^2) ?

The domain of f(x)=(-13)/((x+4)^2) is x -4

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domain of f(x)=(-13)/((x+4)^2)

domain

f (x) = \frac{- 13}{( x + 4 ) ^{2}}

x < - 4 or x > - 4

Interval Notation

(- \infty, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4

The function domain

x < - 4 or x > - 4

f (x) = (\frac{x ^{2} - 9}{x + 3})

h (x) = 1 - x^{2}

y = 4 x - 7

y = 4 x - 5

f (x) = (ln^{2} (x^{2})) - 9

What is the domain of f(x)=(-13)/((x+4)^2) ?
The domain of f(x)=(-13)/((x+4)^2) is x<-4\lor x>-4