What is the domain of f(x)=(sqrt(x-3))/(x^2-4) ?

The domain of f(x)=(sqrt(x-3))/(x^2-4) is x>= 3

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domain of f(x)=(sqrt(x-3))/(x^2-4)

domain

f (x) = \frac{x - 3}{x ^{2} - 4}

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

x \geq 3

f (x) = 2 - 3 lo g_{e} (4 - x)

f (x) = \frac{x}{∣ 2 x + 3 ∣ - 1}

f (x) = - 0.03 x^{2} + x + 6

f (t) = t^{\frac{10}{3}} - \frac{t}{t + 1} + (t^{2} + 2 t)

f (x) = 5 - x + 4

What is the domain of f(x)=(sqrt(x-3))/(x^2-4) ?
The domain of f(x)=(sqrt(x-3))/(x^2-4) is x>= 3