What is the domain of f(x)= 1/(3x-9) ?

The domain of f(x)= 1/(3x-9) is x 3

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domain of f(x)= 1/(3x-9)

domain

f (x) = \frac{1}{3 x - 9}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = x + 1.5

(- 5 x^{2} + 1) \cdot (\frac{1}{x ^{2} + 3})

f (x) = 16 - x^{2}

f (x) = cos (x) + ln (x + 1) d x

y = \frac{1}{x}

What is the domain of f(x)= 1/(3x-9) ?
The domain of f(x)= 1/(3x-9) is x<3\lor x>3