What is the domain of f(x)=\sqrt[6]{x^2-3x} ?

The domain of f(x)=\sqrt[6]{x^2-3x} is x = 3

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domain of f(x)=\sqrt[6]{x^2-3x}

domain

x \leq 0 or x \geq 3

Interval Notation

(- \infty, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

The function domain

x \leq 0 or x \geq 3

f (x) = ln \frac{x + 1}{x + 3}

f (x) = (9 - 2 x) (7 - 2 x) x

1 - \frac{9}{x ^{2}}

4 x - 28

f (x) = 2 x^{2} + 5 x - 12

What is the domain of f(x)=\sqrt[6]{x^2-3x} ?
The domain of f(x)=\sqrt[6]{x^2-3x} is x<= 0\lor x>= 3