What is the domain of sqrt(x^2-9x+14) ?

The domain of sqrt(x^2-9x+14) is x = 7

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domain of sqrt(x^2-9x+14)

domain

x^{2} - 9 x + 14

x \leq 2 or x \geq 7

Interval Notation

(- \infty, 2] \cup [7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 7

The function domain

x \leq 2 or x \geq 7

\frac{5}{4 x ^{\frac{1}{6}}}

f (x) = - 5 - x

f (x) = x - 5 - \frac{2 x - 4}{x ^{2} - 7 x}

f (x) = (2 x - 5) (x^{2} - 5)

f (x) = lo g_{e} (arcsin (x^{2} + 6 x + 9))

What is the domain of sqrt(x^2-9x+14) ?
The domain of sqrt(x^2-9x+14) is x<= 2\lor x>= 7