What is the domain of f(x)= 1/(sqrt(x^2-13x+40)) ?

The domain of f(x)= 1/(sqrt(x^2-13x+40)) is x 8

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domain of f(x)= 1/(sqrt(x^2-13x+40))

domain

f (x) = \frac{1}{x ^{2} - 13 x + 40}

x < 5 or x > 8

Interval Notation

(- \infty, 5) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 5 or x \geq 8

Find undefined (singularity) points:

x = 8, x = 5

Combine real regions and undefined points for final function domain

x < 5 or x > 8

- 5 x - 7

\frac{1}{1 - x - 2}

Y (x) = \frac{1 - ∣ x ∣}{2 - ∣ x ∣}

2 x^{2} + 2 x - 1

What is the domain of f(x)= 1/(sqrt(x^2-13x+40)) ?
The domain of f(x)= 1/(sqrt(x^2-13x+40)) is x<5\lor x>8