What is the domain of f(x)=\sqrt[3]{9-x^2} ?

The domain of f(x)=\sqrt[3]{9-x^2} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{9-x^2}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

- \frac{x - 2}{2 x - 6}

3.90753 x

ln (49 x^{2} - 77 x + 30)

f (x) = \frac{25 x}{12 x - 14}

f (x) = \frac{t}{t ^{2} - 64}

What is the domain of f(x)=\sqrt[3]{9-x^2} ?
The domain of f(x)=\sqrt[3]{9-x^2} is -infinity <x<infinity