What is the domain of f(x)=(sqrt(x+7))/(x-9) ?

The domain of f(x)=(sqrt(x+7))/(x-9) is -7 9

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domain of f(x)=(sqrt(x+7))/(x-9)

domain

f (x) = \frac{x + 7}{x - 9}

- 7 \leq x < 9 or x > 9

Interval Notation

[- 7, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 7 \leq x < 9 or x > 9

f (x) = \frac{4}{\frac{13}{x} - 3}

4 a - 3

\frac{2 + x}{5 - x}

ln (- x^{2} + 2 \cdot x - 1)

f (x) = 2 x^{2} - 2 x + b

What is the domain of f(x)=(sqrt(x+7))/(x-9) ?
The domain of f(x)=(sqrt(x+7))/(x-9) is -7<= x<9\lor x>9