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Popular >

midpoint (0,-2),(4,4)

Solution

midpoint

(0, - 2), (4, 4)

Solution

(2, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 2), (x_{2}, y_{2}) = (4, 4)

= (\frac{4 + 0}{2}, \frac{4 - 2}{2})

Refine

= (2, 1)

Popular Examples

domain of f(x)=|2x-8|domain

f (x) = ∣ 2 x - 8 ∣

distance (2,2),(1,-3)distance

(2, 2), (1, - 3)

inverse of f(x)=(4x)/(x-6)inverse

f (x) = \frac{4 x}{x - 6}

domain of 3/(x-4)domain

\frac{3}{x - 4}

parallel y=4x+6,(-3,3)parallel

y = 4 x + 6, (- 3, 3)

Frequently Asked Questions (FAQ)

What is the midpoint (0,-2),(4,4) ?
The midpoint (0,-2),(4,4) is (2,1)