What is the domain of sqrt(24-(10x-x^2)) ?

The domain of sqrt(24-(10x-x^2)) is x = 6

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domain of sqrt(24-(10x-x^2))

domain

24 - (10 x - x^{2})

x \leq 4 or x \geq 6

Interval Notation

(- \infty, 4] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 4 or x \geq 6

The function domain

x \leq 4 or x \geq 6

ln (\frac{4 x - 8}{2 x + 4})

f (x) = \frac{- 1}{sin ( x )}

f (x) = \frac{1 - x}{x - 2}

f (x) = \frac{x - 7}{x + 4}

f (x) = - a \frac{1}{4} (x + 6) - 4

What is the domain of sqrt(24-(10x-x^2)) ?
The domain of sqrt(24-(10x-x^2)) is x<= 4\lor x>= 6