What is the domain of f(x)=log_{x}(1-e^{1-x}) ?

The domain of f(x)=log_{x}(1-e^{1-x}) is x>1

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domain of f(x)=log_{x}(1-e^{1-x})

domain

f (x) = lo g_{x} (1 - e^{1 - x})

x > 1

Interval Notation

(1, \infty)

Solution steps

Check logs domain:

x > 1

The function domain

x > 1

\frac{( x ^{2} - 6 x - 55 )}{x ^{2} - 3 x - 28}

f (x) = \frac{x ^{2} + 5 x}{x ^{3} - 13 x ^{2} + 36 x}

\frac{\frac{11}{x}}{x + 2}

f (x) = (x + 4) = 0

What is the domain of f(x)=log_{x}(1-e^{1-x}) ?
The domain of f(x)=log_{x}(1-e^{1-x}) is x>1