What is the domain of f(x)=((x-1))/(25-x^2) ?

The domain of f(x)=((x-1))/(25-x^2) is x 5

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domain of f(x)=((x-1))/(25-x^2)

domain

f (x) = \frac{( x - 1 )}{25 - x ^{2}}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{7}{7 x + 1}

y = \frac{1}{2} sin (2 x - 2 π) - 2

f (x) = 3^{x + 1} + 2

f (x) = arcsin (lo g_{2} (x))

f (x) = 3^{x + 1} + 1

What is the domain of f(x)=((x-1))/(25-x^2) ?
The domain of f(x)=((x-1))/(25-x^2) is x<-5\lor-5<x<5\lor x>5