What is the domain of (4x^2+1)/((-2x+1)x) ?

The domain of (4x^2+1)/((-2x+1)x) is x 1/2

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domain of (4x^2+1)/((-2x+1)x)

domain

\frac{4 x ^{2} + 1}{( - 2 x + 1 ) x}

x < 0 or 0 < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, 0) \cup (0, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}, x = 0

The function domain

x < 0 or 0 < x < \frac{1}{2} or x > \frac{1}{2}

f (x) = x^{2} y^{2} - 16 y^{2} + x - 8 = 0

f (x) = \frac{5}{( 4 x - 1 )}

\frac{x ^{2}}{lo g _{e} ( x )}

f (x) = \frac{2 x}{ln ( x )}

(x)^{3} + (x)^{2} - 8 (x) + 5

What is the domain of (4x^2+1)/((-2x+1)x) ?
The domain of (4x^2+1)/((-2x+1)x) is x<0\lor 0<x< 1/2 \lor x> 1/2