What is the extreme f(x)=x^3-3x-1 ?

The extreme f(x)=x^3-3x-1 is Maximum(-1,1),Minimum(1,-3)

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extreme f(x)=x^3-3x-1

extreme points

f (x) = x^{3} - 3 x - 1

Maximum (- 1, 1), Minimum (1, - 3)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x - 1 : 1

Maximum (- 1, 1)

Plug

x = 1

into

x^{3} - 3 x - 1 : - 3

Minimum (1, - 3)

Maximum (- 1, 1), Minimum (1, - 3)

f (x, y) = - 3 x^{2} - 2 y^{2} + 3 x - 4 y + 5

P (x, y) = 36 x^{2} - 9 y^{2}

f (x, y) = \frac{500}{4 + x ^{2} + y ^{2}}

f (x) = x^{3} + 5 x - 4

f (x, y) = 2 y^{2} + 2 x y + x^{2} - 16 x - 20 y

What is the extreme f(x)=x^3-3x-1 ?
The extreme f(x)=x^3-3x-1 is Maximum(-1,1),Minimum(1,-3)