What is the extreme f(x)=2xsqrt(5-5x) ?

The extreme f(x)=2xsqrt(5-5x) is Maximum(2/3 ,(4sqrt(5))/(3sqrt(3))),Minimum(1,0)

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extreme f(x)=2xsqrt(5-5x)

extreme points

f (x) = 2 x 5 - 5 x

Maximum (\frac{2}{3}, \frac{4 5}{3 3}), Minimum (1, 0)

Solution steps

f^{'} (x) = \frac{- 15 x + 10}{5 - 5 x}

Find intervals:

Increasing

: - \infty < x < \frac{2}{3},

Decreasing

: \frac{2}{3} < x < 1

Plug

x = \frac{2}{3}

into

2 x 5 - 5 x : \frac{4 5}{3 3}

Maximum (\frac{2}{3}, \frac{4 5}{3 3})

Plug

x = 1

into

2 x 5 - 5 x : 0

Minimum (1, 0)

Maximum (\frac{2}{3}, \frac{4 5}{3 3}), Minimum (1, 0)

f (x, y) = x^{2} + x y + y^{2} + 2 y

\frac{1}{x ^{2}} + \frac{1}{y} + 2 x y

P (x, y) = 10 x + 12 y

f (x, y) = x^{4} - 2 x^{2} + y^{3} - 3 y

f (x) = 4 x y^{2} - 2 x^{2} y - x

What is the extreme f(x)=2xsqrt(5-5x) ?
The extreme f(x)=2xsqrt(5-5x) is Maximum(2/3 ,(4sqrt(5))/(3sqrt(3))),Minimum(1,0)