What is the extreme f(x)=2x^3+3x^2-36x-5 ?

The extreme f(x)=2x^3+3x^2-36x-5 is Maximum(-3,76),Minimum(2,-49)

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extreme f(x)=2x^3+3x^2-36x-5

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 36 x - 5

Maximum (- 3, 76), Minimum (2, - 49)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 3

into

2 x^{3} + 3 x^{2} - 36 x - 5 : 76

Maximum (- 3, 76)

Plug

x = 2

into

2 x^{3} + 3 x^{2} - 36 x - 5 : - 49

Minimum (2, - 49)

Maximum (- 3, 76), Minimum (2, - 49)

f (x) = (x + 4)^{\frac{2}{3}}

f (x) = - 2 x + 5 ln (2 x)

f (x) = \frac{x ^{3}}{2 - x ^{2}}

f (x) = 2 cos^{2} (x), 0 \leq x \leq π

f (x, y) = x y + \frac{2}{x} + \frac{4}{y}

What is the extreme f(x)=2x^3+3x^2-36x-5 ?
The extreme f(x)=2x^3+3x^2-36x-5 is Maximum(-3,76),Minimum(2,-49)