What is the extreme f(x)=(x^2-11)/(x-6) ?

The extreme f(x)=(x^2-11)/(x-6) is Maximum(1,2),Minimum(11,22)

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extreme f(x)=(x^2-11)/(x-6)

extreme points

f (x) = \frac{x ^{2} - 11}{x - 6}

Maximum (1, 2), Minimum (11, 22)

Solution steps

f^{'} (x) = \frac{x ^{2} - 12 x + 11}{( x - 6 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 6,

Decreasing

: 6 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = 1

into

\frac{x ^{2} - 11}{x - 6} : 2

Maximum (1, 2)

Plug

x = 11

into

\frac{x ^{2} - 11}{x - 6} : 22

Minimum (11, 22)

Maximum (1, 2), Minimum (11, 22)

\frac{1}{4} - \frac{3}{2} x

2 x - 3

f (x) = (\frac{x ^{2}}{x + 1})

P (x, y) = - 3 x + 4 y

\frac{3 ^{x} + 5}{9}

What is the extreme f(x)=(x^2-11)/(x-6) ?
The extreme f(x)=(x^2-11)/(x-6) is Maximum(1,2),Minimum(11,22)