What is the extreme f(x)=2x^3-9x^2+12x+6 ?

The extreme f(x)=2x^3-9x^2+12x+6 is Maximum(1,11),Minimum(2,10)

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extreme f(x)=2x^3-9x^2+12x+6

extreme points

f (x) = 2 x^{3} - 9 x^{2} + 12 x + 6

Maximum (1, 11), Minimum (2, 10)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x + 12

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 1

into

2 x^{3} - 9 x^{2} + 12 x + 6 : 11

Maximum (1, 11)

Plug

x = 2

into

2 x^{3} - 9 x^{2} + 12 x + 6 : 10

Minimum (2, 10)

Maximum (1, 11), Minimum (2, 10)

f (x) = x + ln (1 - x)

f (x) = 7 x ln (x)

f (x) = x^{2} + x y + y^{2} - 16 y + 85

f (x, y) = 7 - x^{4} + 2 x^{2} - y^{2}

x + 1

What is the extreme f(x)=2x^3-9x^2+12x+6 ?
The extreme f(x)=2x^3-9x^2+12x+6 is Maximum(1,11),Minimum(2,10)