What is the extreme f(x,y)= 1/2 (x^2-y^2) ?

The extreme f(x,y)= 1/2 (x^2-y^2) is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)= 1/2 (x^2-y^2)

extreme points

f (x, y) = \frac{1}{2} (x^{2} - y^{2})

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 1

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 4 sin (x) + 4 cos (x)

f (x) = x^{2} + 2 y^{2}

f (x) = \frac{6}{x + 7}

f (x) = - 5 x + 3 ln (4 x), (0, 4)

f (x) = x^{2} y - 15 x y^{2} + 12 y

What is the extreme f(x,y)= 1/2 (x^2-y^2) ?
The extreme f(x,y)= 1/2 (x^2-y^2) is Saddle(0,0)