What is the extreme f(x)=4x^3e^{-x} ?

The extreme f(x)=4x^3e^{-x} is Saddle(0,0),Maximum(3,(108)/(e^3))

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extreme f(x)=4x^3e^{-x}

extreme points

f (x) = 4 x^{3} e^{- x}

Saddle (0, 0), Maximum (3, \frac{108}{e ^{3}})

Solution steps

Find the critical points:

x = 0, x = 3

Domain of

4 x^{3} e^{- x} : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug the extreme point

x = 0

into

4 x^{3} e^{- x} \Rightarrow y = 0

Saddle (0, 0)

Plug the extreme point

x = 3

into

4 x^{3} e^{- x} \Rightarrow y = \frac{108}{e ^{3}}

Maximum (3, \frac{108}{e ^{3}})

Saddle (0, 0), Maximum (3, \frac{108}{e ^{3}})

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What is the extreme f(x)=4x^3e^{-x} ?
The extreme f(x)=4x^3e^{-x} is Saddle(0,0),Maximum(3,(108)/(e^3))