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Popular >

extreme f(x)= 8/(x^2+2)

Solution

extreme points

f (x) = \frac{8}{x ^{2} + 2}

Solution

Maximum (0, 4)

Solution steps

f^{'} (x) = - \frac{16 x}{( x ^{2} + 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{8}{x ^{2} + 2} : 4

Maximum (0, 4)

Popular Examples

extreme f(x,y)=2x^3+6xy+3y^2 extreme points

f (x, y) = 2 x^{3} + 6 x y + 3 y^{2}

extreme g(x,y)=x^2y^3+x^4y+3y^2 extreme points

g (x, y) = x^{2} y^{3} + x^{4} y + 3 y^{2}

extreme f(x,y)=-2x^2-y^2+8x+10y-5xy extreme points

f (x, y) = - 2 x^{2} - y^{2} + 8 x + 10 y - 5 x y

extreme f(x,y)=4xy^2-2x^2y-x extreme points

f (x, y) = 4 x y^{2} - 2 x^{2} y - x

extreme (6-2a)/(sqrt(30))extreme points

\frac{6 - 2 a}{30}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 8/(x^2+2) ?
The extreme f(x)= 8/(x^2+2) is Maximum(0,4)