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Popular >

extreme f(x)=x^3-3x+7

Solution

extreme points

f (x) = x^{3} - 3 x + 7

Solution

Maximum (- 1, 9), Minimum (1, 5)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 7 : 9

Maximum (- 1, 9)

Plug

x = 1

into

x^{3} - 3 x + 7 : 5

Minimum (1, 5)

Maximum (- 1, 9), Minimum (1, 5)

Popular Examples

extreme f(x)=y^4-4y^3+2x^2+8xy extreme points

f (x) = y^{4} - 4 y^{3} + 2 x^{2} + 8 x y

extreme f(x)=x^2e^{-9x}extreme points

f (x) = x^{2} e^{- 9 x}

extreme f(x,y)=xy-x^2-y^2-2x-2y+4 extreme points

f (x, y) = x y - x^{2} - y^{2} - 2 x - 2 y + 4

extreme y=(ln(x))/x extreme points

y = \frac{ln ( x )}{x}

extreme x^2+y^2+x^2y+4 extreme points

x^{2} + y^{2} + x^{2} y + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-3x+7 ?
The extreme f(x)=x^3-3x+7 is Maximum(-1,9),Minimum(1,5)