What is the extreme f(x)=(pir^2)/2+((76-pix-x))/2*x ?

The extreme f(x)=(pir^2)/2+((76-pix-x))/2*x is Saddle((38)/(pi+1),0)

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extreme f(x)=(pir^2)/2+((76-pix-x))/2*x

extreme points

f (x) = \frac{π r ^{2}}{2} + \frac{( 76 - π x - x )}{2} \cdot x

Saddle (\frac{38}{π + 1}, 0)

Solution steps

Find the critical points:

(\frac{38}{π + 1}, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = π

D (x, r) = - π^{2} - π

Check the sign of at each critical point

Check critical point

(\frac{38}{π + 1}, 0) :

Saddle

Saddle (\frac{38}{π + 1}, 0)

10 x^{2} y - 5 x^{2} - 4 y^{2} - x^{4} - 2 y^{4}

f (x, y) = x^{2} + y^{2} - 2 y + 1

36 - x^{2} - x + 3

f (x, y) = (x^{2} + y) e^{\frac{y}{2}}

h (t, v) = 5 t^{2} + v t

What is the extreme f(x)=(pir^2)/2+((76-pix-x))/2*x ?
The extreme f(x)=(pir^2)/2+((76-pix-x))/2*x is Saddle((38)/(pi+1),0)