What is the extreme f(x)=x^3-3x^2-9x+15 ?

The extreme f(x)=x^3-3x^2-9x+15 is Maximum(-1,20),Minimum(3,-12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x^2-9x+15

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 15

Maximum (- 1, 20), Minimum (3, - 12)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 15 : 20

Maximum (- 1, 20)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 15 : - 12

Minimum (3, - 12)

Maximum (- 1, 20), Minimum (3, - 12)

f (x) = x^{4} - 8 x^{3} + 3

f (x) = x^{3} - 2 x^{4}

x^{\frac{1}{3}} (x + 4)

f (x, y) = x y (7 + x) (y - 3)

f (x) = \frac{1}{x - 5}

What is the extreme f(x)=x^3-3x^2-9x+15 ?
The extreme f(x)=x^3-3x^2-9x+15 is Maximum(-1,20),Minimum(3,-12)