What is the extreme f(x,y)=x^2y-5xy^3 ?

The extreme f(x,y)=x^2y-5xy^3 is None

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extreme f(x,y)=x^2y-5xy^3

extreme points

f (x, y) = x^{2} y - 5 x y^{3}

None

Solution steps

Find the critical points:

None

x^{2} y - 5 x y^{3}

has no critical points, therefore there are no extreme points

None

\frac{x + 4}{x - 3}

f (x, y) = 4 x y^{2} - 2 x^{2} y - x

f (x, y) = 14 x^{2} - 2 x^{3} + 4 x y

f (x) = \frac{1}{3} x^{3} - 5 x^{2} + 21 x - 16

f (x, y) = x^{2} y - x y + 3 y^{2}