What is the extreme f(x)=(7(x-1)^2)/(x+9),(-21,-9) ?

The extreme f(x)=(7(x-1)^2)/(x+9),(-21,-9) is Maximum(-19,-280)

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extreme f(x)=(7(x-1)^2)/(x+9),(-21,-9)

extreme points

f (x) = \frac{7 ( x - 1 ) ^{2}}{x + 9}, (- 21, - 9)

Maximum (- 19, - 280)

Solution steps

Find the critical points:

x = - 19

Domain of

\frac{7 ( x - 1 ) ^{2}}{x + 9}, (- 21, - 9) : - 21 < x < - 9

Find intervals:

Increasing

: - 21 < x < - 19,

Decreasing

: - 19 < x < - 9

Plug the extreme point

x = - 19

into

\frac{7 ( x - 1 ) ^{2}}{x + 9} \Rightarrow y = - 280

Maximum (- 19, - 280)

\frac{7 x - 2}{3}

f (x) = x^{3} + y^{3} - 21 x y

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 6 y^{2} - 9 x

h (x) = x^{3} - 12 x

f (x) = x^{2} - 11

What is the extreme f(x)=(7(x-1)^2)/(x+9),(-21,-9) ?
The extreme f(x)=(7(x-1)^2)/(x+9),(-21,-9) is Maximum(-19,-280)